7x^2-4x=5

Solution for 7x^2-4x=5 equation:

7x^2-4x=5

We move all terms to the left:

7x^2-4x-(5)=0

a = 7; b = -4; c = -5;
Δ = b2-4ac
Δ = -42-4·7·(-5)
Δ = 156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{156}=\sqrt{4*39}=\sqrt{4}*\sqrt{39}=2\sqrt{39}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-2\sqrt{39}}{2*7}=\frac{4-2\sqrt{39}}{14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+2\sqrt{39}}{2*7}=\frac{4+2\sqrt{39}}{14}
$